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高中所有化學(xué)方程式,高中化學(xué)方程式大全( 二 )


高中所有化學(xué)方程式,高中化學(xué)方程式大全


2,高中化學(xué)方程式是什么金屬氧化物類方程式1、低價態(tài)的還原性:6FeO+O2===2Fe3O4FeO+4HNO3===Fe(NO3)3+NO2+2H2OFeO+4H++NO3―=Fe3++NO2↑+2H2O2、氧化性:Na2O2+2Na2Na2O(此反應(yīng)用于制備Na2O)MgO,Al2O3幾乎沒有氧化性,很難被還原為Mg,Al.一般通過電解制Mg和Al.Fe2O3+3H22Fe+3H2O(制還原鐵粉)Fe3O4+4H23Fe+4H2OCuO+H2Cu+H2O2Fe3O4+16HI==6FeI2+8H2O+2I22Fe3O4+16H++4I―=6Fe2++8H2O+2I2Fe2O3+Fe3FeO(煉鋼過程中加入廢鋼作氧化劑)FeO+CFe+CO(高溫?zé)掍撜{(diào)節(jié)C含量)2FeO+Si2Fe+SiO2(高溫?zé)掍撜{(diào)節(jié)Si含量)3、與水的作用:Na2O+H2O==2NaOHNa2O+H2O=2Na++2OH–2Na2O2+2H2O===4NaOH+O2↑2Na2O2+2H2O=4Na++4OH–+O2↑(此反應(yīng)分兩步:Na2O2+2H2O===2NaOH+H2O2;2H2O2===2H2O+O2H2O2的制備可利用類似的反應(yīng):BaO2+H2SO4(稀)===BaSO4+H2O2)MgO+H2O===Mg(OH)2(緩慢反應(yīng))4、與酸性物質(zhì)的作用:Na2O+SO3==Na2SO4Na2O+CO2==Na2CO3MgO+SO3===MgSO4Na2O+2HCl==2NaCl+H2ONa2O+2H+=2Na++H2O2Na2O2+2CO2==2Na2CO3+O2↑Na2O2+H2SO4(冷,稀)===Na2SO4+H2O2MgO+H2SO4===MgSO4+H2OMgO+2H+=Mg2++H2OAl2O3+3H2SO4===Al2(SO4)3+3H2OAl2O3+6H+=2Al3++3H2OAl2O3+2NaOH===2NaAlO2+H2O(Al2O3兩性氧化物)Al2O3+2OH―=2AlO2―+H2OFeO+2HCl===FeCl2+H2OFeO+2H+=Fe2++H2OFe2O3+6HCl===2FeCl3+3H2OFe??2O3+6H+=2Fe3++3H2OFe3O4+8HCl===FeCl2+2FeCl3+4H2OFe3O4+8H+=2Fe3++Fe2++4H2O2含氧酸類方程式1、氧化性:4HClO3+3H2S===3H2SO4+4HClClO3–+3H2S=6H++SO42–+Cl–HClO3+HI===HIO3+HClClO3–+I(xiàn)–=IO3–+Cl–3HClO+HI===HIO3+3HCl3HClO+I-=IO3–+3H++Cl–HClO+H2SO3===H2SO4+HClHClO+H2SO3=3H++SO42–+Cl–HClO+H2O2===HCl+H2O+O2↑HClO+H2O2=H++Cl–+H2O+O2↑(氧化性:HClO>HClO2>HClO3>HClO4,但濃,熱的HClO4氧化性很強(qiáng))2H2SO4(濃)+CCO2↑+2SO2↑+2H2O2H2SO4(濃)+S3SO2↑+2H2OH2SO4+Fe(Al)室溫下鈍化6H2SO4(濃)+2FeFe2(SO4)3+3SO2↑+6H2O2H2SO4(濃)+CuCuSO4+SO2↑+2H2OH2SO4(濃)+2HBr===SO2↑+Br2+2H2O(不能用濃硫酸與NaBr制取HBr)H2SO4(濃)+2HI===SO2↑+I(xiàn)2+2H2O(不能用濃硫酸與NaI制取HI)H2SO4(?。獸e===FeSO4+H2↑2H++Fe=Fe2++H2↑H2SO3+2H2S===3S↓+3H2O4HNO3(濃)+CCO2↑+4NO2↑+2H2O6HNO3(濃)+SH2SO4+6NO2↑+2H2O5HNO3(濃)+PH3PO4+5NO2↑+H2O5HNO3(稀)+3P+2H2O3H3PO4+5NO↑5H++5NO3-+3P+2H2O3H3PO4+5NO↑6HNO3(濃足)+Fe===Fe(NO3)3+3NO2↑+3H2O4HNO3(濃)+Fe(足)===Fe(NO3)2+NO2↑+2H2O(先得Fe3+,在Fe過量時再生成Fe2+的鹽)4HNO3(稀足)+Fe===Fe(NO3)3+NO↑+2H2O4H++NO3-+Fe=Fe3++NO↑+2H2O30HNO3+8Fe===8Fe(NO3)3+3N2O↑+15H2O30H++6NO3–+8Fe=8Fe3++3N2O↑+15H2O36HNO3+10Fe===10Fe(NO3)3+3N2↑+18H2O36H++6NO3–+10Fe=8Fe3++3N2↑+18H2O30HNO3+8Fe===8Fe(NO3)3+3NH4NO3+9H2O30H++3NO3–+8Fe=8Fe3++3NH4++9H2O4Zn+10HNO3(?。?4Zn(NO3)2+N2O↑+5H2O4Zn+10H++2NO3–=4Zn2++N2O↑+5H2O4Zn+10HNO3(稀)==4Zn(NO3)2+NH4NO3+3H2O4Zn+10H++NO3–=4Zn2++NH4++5H2O2、還原性:H2SO3+X2+H2O===H2SO4+2HX(X表示Cl2,Br2,I2)H2SO3+X2+H2O=4H++SO42-+X–2H2SO3+O2==2H2SO42H2SO3+O2=4H++SO42-H2SO3+H2O2===H2SO4+H2OH2SO3+H2O2=2H++SO42–+H2O5H2SO3+2KMnO4===2MnSO4+K2SO4+2H2SO4+3H2O5H2SO3+2MnO4–=2Mn2++4H++3SO42–+3H2OH2SO3+2FeCl3+H2O===H2SO4+2FeCl2+2HClH2SO3+2Fe3++H2O=4H++2Fe2++SO42–3、酸性:H2SO4(濃)+CaF2CaSO4+2HF↑(不揮發(fā)性酸制取揮發(fā)性酸)H2SO4(濃)+NaClNaHSO4+HCl↑(不揮發(fā)性酸制取揮發(fā)性酸)H2SO4(濃)+2NaClNa2SO4+2HCl↑(不揮發(fā)性酸制取揮發(fā)性酸)H2SO4(濃)+NaNO3NaHSO4+HNO3↑(不揮發(fā)性酸制取揮發(fā)性酸)3H2SO4(濃)+Ca3(PO4)23CaSO4+2H3PO4(強(qiáng)酸制弱酸酸)2H2SO4(濃)+Ca3(PO4)22CaSO4+Ca(H2PO4)2(工業(yè)制磷肥)3HNO3+Ag3PO4==H3PO4+3AgNO33H++Ag3PO4=H3PO4+3Ag+2HNO3+CaCO3==Ca(NO3)2+H2O+CO2↑2H++CaCO3=Ca2++H2O+CO2↑(用HNO3和濃H2SO4不能制備H2S,HI,HBr,SO2等還原性氣體)4H3PO4+Ca3(PO4)23Ca(H2PO4)2(重鈣)H3PO4(濃)+NaBrNaH2PO4+HBr↑(不揮發(fā)性酸制取揮發(fā)性酸,磷酸是非氧化性酸)H3PO4(濃)+NaINaH2PO4+HI↑4、不穩(wěn)定性:2HClO2HCl+O2↑(保存在棕色瓶中)4HNO34NO2↑+O2↑+2H2O(保存在棕色瓶中)H2SO3H2O+SO2↑(在加熱或酸性條件下分解)H2CO3H2O+CO2↑(在加熱或酸性條件下分解)H4SiO4H2SiO3+H2OH2SiO3SiO2↓+H2OH2S2O3H2O+S↓+SO2↑(在加熱或酸性條件下分解)堿類方程式1、低價態(tài)的還原性:4Fe(OH)2+O2+2H2O===4Fe(OH)32、與酸性物質(zhì)的作用:2NaOH+SO2(少量)==Na2SO3+H2OOH–+SO2=SO32–+H2ONaOH+SO2(足)==NaHSO3OH-+SO2(足)=HSO3–2NaOH+SiO2==Na2SiO3+H2OOH-+SiO2=SiO32–+H2O2NaOH+Al2O3==2NaAlO2+H2O2OH-+Al2O3=2AlO2–+H2O2KOH+Cl2==KCl+KClO+H2OCl2+2OH–=Cl–+ClO–+H2ONaOH+HCl==NaCl+H2OH++OH=H2ONaOH+H2S(足)==NaHS+H2OOH–+H2S=HS–+H2O2NaOH+H2S(少量)==Na2S+2H2O2OH–+H2S=S2–+2H2O3NaOH+AlCl3==Al(OH)3↓+3NaCl3OH–+Al3+=Al(OH)3↓NaOH+Al(OH)3==NaAlO2+2H2O(AlCl3和Al(OH)3哪個酸性強(qiáng)?)OH–+Al(OH)3=AlO2–+2H2OCa(OH)2+2NH4Cl2CaCl2+2NH3↑+2H2O(實驗室制NH3)NaOH+NH4ClNaCl+NH3↑+H2OMg(OH)2+2NH4Cl==MgCl2+2NH3??H2O(Al(OH)3+NH4Cl不溶解)Ba(OH)2+H2SO4==BaSO4↓+2H2O2H++2OH–+Ba2++SO42–=BaSO4↓2H2O3、不穩(wěn)定性:Mg(OH)2MgO+H2O2Al(OH)3Al2O3+3H2O2Fe(OH)3Fe2O3+3H2OCu(OH)2CuO+H2O2AgOH==Ag2O+H2O

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